Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 15:37Z
d/dz [z^3] = 3z^2
∑_{k=1}^{n} k = n(n+1)/2
75K
det| 7 4 ; 4 8 | = 40
479K
6φ² + 8φ + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
129K
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
390K
det| 5 9 ; 0 6 | = 30
153K