Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:24Z
∇²α = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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6φ² + 8φ + 4 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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∂φ/∂φ = 1φ
\frac{2}{2} \sum_{i=1}^{n} i^{2}
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det| 4 8 ; 1 5 | = 12
det| 7 4 ; 4 8 | = 40
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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇²r = 0
det| 12 9 ; 2 13 | = 138
\frac{8}{5} \sum_{i=1}^{n} i^{2}