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Math Dump /sym/7fd97a

id=1 · host=jp.commstar.world · 2026-10-19 16:38Z

7φ² + 4φ + 5 = 0

∑_{k=1}^{n} k = n(n+1)/2

326K

N₂ + 3H₂ ⇌ 2NH₃

198K

E = mc²

\binom{n}{k} = \frac{n!}{k!(n-k)!}

155K

∑_{k=1}^{n} k = n(n+1)/2

63K

e^{i\pi} + 1 = 0

ω = 2πf

366K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

201K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

iħ ∂ψ/∂t = Ĥψ

176K

2H₂ + O₂ → 2H₂O

319K

d/dβ [β^2] = 2β^1

8ψ² + 7ψ + 0 = 0

359K

F = G m₁m₂ / r²

263K

PV = nRT

233K

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