Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 22:11Z
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
234K
3β² + 9β + 4 = 0
det| 7 4 ; 4 8 | = 40
392K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
233K
ω = 2πf
det| 3 7 ; 2 4 | = -2
100K
∑_{k=1}^{n} k = n(n+1)/2
330K
12t² + 5t + 7 = 0