Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:23Z
11t² + 7t + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
198K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-φ²) dφ = √π / 2
366K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 11 5 ; 0 12 | = 132
359K
det| 10 1 ; 4 11 | = 106