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Math Dump /sym/7fd97a

id=1 · host=jp.commstar.world · 2026-10-19 18:07Z

∇²α = 0
ops_8252.eqn
∫₀^∞ e^(-x²) dx = √π / 2
326K
eq_9391.mol
e^{i\pi} + 1 = 0
198K
6φ² + 8φ + 4 = 0
spec_5686.mol
∑_{k=1}^{n} k = n(n+1)/2
155K
rxn_5376.log
det| 4 6 ; 4 5 | = -4
63K
∂φ/∂φ = 1φ
rxn_0414.log
det| 9 4 ; 1 10 | = 86
366K
eq_9442.mol
e^{i\pi} + 1 = 0
201K
det| 4 8 ; 1 5 | = 12
spec_4768.mol
∑_{k=1}^{n} k = n(n+1)/2
176K
spec_7724.csv
d/dt [t^3] = 3t^2
319K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
eq_1210.eqn
det| 3 6 ; 0 4 | = 12
359K
7φ² + 2φ + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇²r = 0
det| 12 9 ; 2 13 | = 138
\frac{8}{5} \sum_{i=1}^{n} i^{2}
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