Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:58Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
479K
3β² + 6β + 2 = 0
det| 1 1 ; 5 2 | = -3
276K
∫₀^∞ e^(-φ²) dφ = √π / 2
129K
F = ma
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-t²) dt = √π / 2
1K