Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:43Z
2ψ² + 5ψ + 4 = 0
N₂ + 3H₂ ⇌ 2NH₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\lim_{α\to 0} \frac{\sin α}{α} = 1
390K
∇²z = 0
det| 11 9 ; 5 12 | = 87
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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