Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:36Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
F = ma
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 5 9 ; 0 6 | = 30
153K
1x² + 5x + 7 = 0
det| 9 4 ; 1 10 | = 86
473K
d/dy [y^11] = 11y^10
188K