Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:34Z
11t² + 7t + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
198K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
366K
CH₄ + 2O₂ → CO₂ + 2H₂O
AgNO₃ + NaCl → AgCl↓ + NaNO₃
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
359K
det| 7 4 ; 4 8 | = 40
263K
det| 10 1 ; 4 11 | = 106
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
iħ ∂ψ/∂t = Ĥψ