Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:35Z
11t² + 7t + 4 = 0
det| 9 4 ; 1 10 | = 86
198K
E = mc²
det| 5 2 ; 3 6 | = 24
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
176K
∑_{k=1}^{n} k = n(n+1)/2
319K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
359K
ΔS ≥ 0