Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:14Z
11t² + 7t + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
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∫₀^∞ e^(-z²) dz = √π / 2
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E = mc²
∑_{k=1}^{n} k = n(n+1)/2
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 5 6 ; 2 6 | = 18
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det| 10 2 ; 1 11 | = 108
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CH₄ + 2O₂ → CO₂ + 2H₂O
det| 4 8 ; 3 5 | = -4
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det| 9 4 ; 1 10 | = 86
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∫₀^∞ e^(-ψ²) dψ = √π / 2
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