Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:28Z
∑_{k=1}^{n} k = n(n+1)/2
det| 5 9 ; 7 6 | = -33
75K
3β² + 6β + 2 = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
129K
F = ma
det| 7 4 ; 4 8 | = 40
191K
det| 1 4 ; 3 2 | = -10
153K
∑_{k=1}^{n} k = n(n+1)/2
473K
det| 5 9 ; 0 6 | = 30
338K