Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:41Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
479K
8β² + 2β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
det| 5 6 ; 7 6 | = -12
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∑_{k=1}^{n} k = n(n+1)/2
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 1 4 ; 3 2 | = -10
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det| 12 1 ; 1 13 | = 155
∑_{k=1}^{n} k = n(n+1)/2
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det| 7 4 ; 4 8 | = 40
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N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-θ²) dθ = √π / 2
det| 5 5 ; 2 6 | = 20
e^{i\pi} + 1 = 0