Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:36Z
∇²α = 0
∑_{k=1}^{n} k = n(n+1)/2
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6φ² + 8φ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
63K
∂φ/∂φ = 1φ
det| 9 4 ; 1 10 | = 86
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
176K
∑_{k=1}^{n} k = n(n+1)/2
319K
det| 5 2 ; 3 6 | = 24
359K