Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:01Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
479K
3β² + 6β + 2 = 0
det| 7 4 ; 4 8 | = 40
129K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
191K
∑_{k=1}^{n} k = n(n+1)/2
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
1K
1x² + 5x + 7 = 0
∇²ψ = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
188K
3φ² + 8φ + 6 = 0