Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 07:46Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
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7r² + 8r + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 3 1 ; 7 4 | = 5
366K
det| 7 9 ; 1 8 | = 47
201K
det| 10 9 ; 3 11 | = 83
2ψ² + 6ψ + 0 = 0
ω = 2πf
∂ψ/∂t = 3ψ
6θ² + 3θ + 6 = 0
det| 8 4 ; 5 9 | = 52