Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:37Z
∇²α = 0
det| 7 4 ; 4 8 | = 40
326K
6φ² + 8φ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
155K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
63K
∂φ/∂φ = 1φ
det| 11 9 ; 5 12 | = 87
366K
det| 11 5 ; 0 12 | = 132
201K
det| 4 8 ; 1 5 | = 12
∫₀^∞ e^(-t²) dt = √π / 2
319K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
7φ² + 2φ + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O