Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:41Z
2ψ² + 5ψ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
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N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
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\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
det| 9 4 ; 1 10 | = 86
191K
∇²z = 0
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-φ²) dφ = √π / 2
473K