Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:55Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-n²) dn = √π / 2
75K
∫₀^∞ e^(-z²) dz = √π / 2
479K
3β² + 6β + 2 = 0
det| 7 4 ; 4 8 | = 40
276K
F = ma
det| 5 6 ; 7 6 | = -12
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
1K
∫₀^∞ e^(-ψ²) dψ = √π / 2
473K