Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 19:35Z
∂r/∂φ = 2r
∫₀^∞ e^(-z²) dz = √π / 2
198K
e^{i\pi} + 1 = 0
det| 7 4 ; 4 8 | = 40
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-x²) dx = √π / 2
366K
\oint_C \vec{F}\cdot d\vec{r} = 0
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\oint_C \vec{F}\cdot d\vec{r} = 0
det| 4 8 ; 3 5 | = -4
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∫₀^∞ e^(-ψ²) dψ = √π / 2
359K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
412K