Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:27Z
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
75K
∫₀^∞ e^(-z²) dz = √π / 2
479K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
F = ma
10n² + 4n + 5 = 0
det| 10 9 ; 0 11 | = 110
1K
det| 1 4 ; 0 2 | = 2
473K
∫₀^∞ e^(-t²) dt = √π / 2
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