Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 16:55Z
7φ² + 4φ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
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∫₀^∞ e^(-t²) dt = √π / 2
198K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
63K
e^{i\pi} + 1 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 7 4 ; 4 8 | = 40
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det| 3 7 ; 2 4 | = -2
359K