Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 15:19Z
\lim_{y\to 0} \frac{\sin y}{y} = 1
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-n²) dn = √π / 2
63K
det| 8 8 ; 0 9 | = 72
det| 3 7 ; 2 4 | = -2
366K
λ = h/p
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 5 9 ; 7 6 | = -33
359K
det| 9 4 ; 1 10 | = 86
263K
8x² + 1x + 3 = 0
\lim_{t\to 0} \frac{\sin t}{t} = 1
233K
det| 11 8 ; 3 12 | = 108
∇ × E = −∂B/∂t
F = ma