Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:39Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 4 ; 5 5 | = 0
479K
8β² + 2β + 0 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
129K
∑_{k=1}^{n} k = n(n+1)/2
det| 9 4 ; 1 10 | = 86
191K
∑_{k=1}^{n} k = n(n+1)/2
390K
\lim_{r\to 0} \frac{\sin r}{r} = 1
∑_{k=1}^{n} k = n(n+1)/2
1K
det| 12 1 ; 1 13 | = 155
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-θ²) dθ = √π / 2