Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:39Z
∇ × E = −∂B/∂t
det| 4 6 ; 4 5 | = -4
479K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
191K
10n² + 4n + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
153K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 5 2 ; 3 6 | = 24
473K
∫₀^∞ e^(-γ²) dγ = √π / 2
∫₀^∞ e^(-n²) dn = √π / 2
188K
det| 6 9 ; 4 7 | = 6
det| 9 5 ; 1 10 | = 85