Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:37Z
∇²α = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
326K
∫₀^∞ e^(-φ²) dφ = √π / 2
198K
6φ² + 8φ + 4 = 0
∂φ/∂φ = 1φ
det| 4 8 ; 1 5 | = 12
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
Fe₂O₃ + 3CO → 2Fe + 3CO₂
263K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇²r = 0