Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:34Z
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
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\frac{8}{9} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
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det| 6 6 ; 3 7 | = 24
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F = ma
∑_{k=1}^{n} k = n(n+1)/2
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10n² + 4n + 5 = 0
det| 11 9 ; 5 12 | = 87
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