Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 14:27Z
∫₀^∞ e^(-ψ²) dψ = √π / 2
e^{i\pi} + 1 = 0
det| 4 8 ; 3 5 | = -4
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det| 11 9 ; 0 12 | = 132
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2H₂ + O₂ → 2H₂O
det| 11 9 ; 5 12 | = 87
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-t²) dt = √π / 2
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