Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:24Z
∑_{k=1}^{n} k = n(n+1)/2
det| 12 1 ; 4 13 | = 152
75K
CH₄ + 2O₂ → CO₂ + 2H₂O
479K
3β² + 6β + 2 = 0
det| 8 9 ; 4 9 | = 36
276K
F = ma
∑_{k=1}^{n} k = n(n+1)/2
191K
det| 9 4 ; 1 10 | = 86
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
1K
∑_{k=1}^{n} k = n(n+1)/2
338K