Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 07:51Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
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7r² + 8r + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 9 4 ; 1 10 | = 86
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det| 5 3 ; 2 6 | = 24
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∑_{k=1}^{n} k = n(n+1)/2
319K
det| 5 2 ; 3 6 | = 24
359K