Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 07:46Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
198K
7r² + 8r + 6 = 0
det| 7 4 ; 4 8 | = 40
155K
∑_{k=1}^{n} k = n(n+1)/2
det| 1 4 ; 3 2 | = -10
201K
det| 10 9 ; 3 11 | = 83
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
176K
2ψ² + 6ψ + 0 = 0