Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 08:21Z
∑_{k=1}^{n} k = n(n+1)/2
11n² + 1n + 0 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
Fe₂O₃ + 3CO → 2Fe + 3CO₂
390K
4y² + 8y + 1 = 0
det| 11 7 ; 4 12 | = 104
∑_{k=1}^{n} k = n(n+1)/2
338K
d/dy [y^11] = 11y^10
188K