Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 16:08Z
7φ² + 4φ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
198K
E = mc²
Fe₂O₃ + 3CO → 2Fe + 3CO₂
155K
e^{i\pi} + 1 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
176K
det| 7 4 ; 4 8 | = 40
319K
d/dβ [β^2] = 2β^1
det| 5 2 ; 3 6 | = 24
359K
det| 9 1 ; 5 10 | = 85