Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:25Z
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
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\frac{8}{9} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
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F = ma
CH₄ + 2O₂ → CO₂ + 2H₂O
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∫₀^∞ e^(-n²) dn = √π / 2
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10n² + 4n + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
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d/dy [y^11] = 11y^10
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det| 7 4 ; 4 8 | = 40
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