Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-21 01:17Z
\frac{3}{4} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
352K
∂t/∂φ = 7t
\frac{4}{2} \sum_{i=1}^{n} i^{2}
det| 9 4 ; 1 10 | = 86
434K
∫₀^∞ e^(-β²) dβ = √π / 2
det| 4 8 ; 3 5 | = -4
63K
∑_{k=1}^{n} k = n(n+1)/2
ΔS ≥ 0
1γ² + 6γ + 2 = 0