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Math Dump /sym/7fd97a

id=1 · host=jp.commstar.world · 2026-10-19 16:48Z

7φ² + 4φ + 5 = 0

∇²r = 0

326K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

198K

E = mc²

∇ × E = −∂B/∂t

155K

d/dt [t^3] = 3t^2

63K

e^{i\pi} + 1 = 0

F = G m₁m₂ / r²

366K

det| 10 4 ; 1 11 | = 106

201K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

E = mc²

176K

PV = nRT

319K

d/dβ [β^2] = 2β^1

det| 3 6 ; 0 4 | = 12

359K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

263K

det| 9 1 ; 5 10 | = 85

8ψ² + 7ψ + 0 = 0

233K

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