Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 00:29Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
479K
7x² + 6x + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
191K
det| 10 4 ; 1 11 | = 106
390K
5β² + 9β + 2 = 0
det| 3 6 ; 0 4 | = 12
153K
e^{i\pi} + 1 = 0
det| 7 4 ; 4 8 | = 40
473K
∇²β = 0