Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:40Z
∑_{k=1}^{n} k = n(n+1)/2
det| 8 9 ; 4 9 | = 36
75K
∫₀^∞ e^(-z²) dz = √π / 2
479K
8β² + 2β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
191K
det| 5 6 ; 7 6 | = -12
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\lim_{r\to 0} \frac{\sin r}{r} = 1
∫₀^∞ e^(-ψ²) dψ = √π / 2
473K
CH₄ + 2O₂ → CO₂ + 2H₂O
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
188K
∫₀^∞ e^(-t²) dt = √π / 2
416K