Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:38Z
∑_{k=1}^{n} k = n(n+1)/2
8β² + 2β + 0 = 0
det| 5 3 ; 2 6 | = 24
129K
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
390K
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 5 2 ; 3 6 | = 24
473K