Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:25Z
∇²α = 0
∫₀^∞ e^(-x²) dx = √π / 2
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∑_{k=1}^{n} k = n(n+1)/2
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6φ² + 8φ + 4 = 0
∫₀^∞ e^(-t²) dt = √π / 2
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det| 11 9 ; 5 12 | = 87
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∂φ/∂φ = 1φ
det| 7 4 ; 4 8 | = 40
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det| 4 8 ; 1 5 | = 12
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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