Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 08:21Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
11n² + 1n + 0 = 0
det| 6 6 ; 3 7 | = 24
129K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 7 4 ; 4 8 | = 40
191K
4y² + 8y + 1 = 0
det| 11 7 ; 4 12 | = 104
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
188K
ω = 2πf