Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:32Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
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3β² + 6β + 2 = 0
det| 1 4 ; 0 2 | = 2
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F = ma
∑_{k=1}^{n} k = n(n+1)/2
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CH₄ + 2O₂ → CO₂ + 2H₂O
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Fe₂O₃ + 3CO → 2Fe + 3CO₂
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