Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:53Z
2ψ² + 5ψ + 4 = 0
det| 4 6 ; 4 5 | = -4
75K
N₂ + 3H₂ ⇌ 2NH₃
det| 5 6 ; 2 6 | = 18
276K
∫₀^∞ e^(-n²) dn = √π / 2
129K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∇²z = 0
det| 5 6 ; 7 6 | = -12
1K
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-t²) dt = √π / 2
473K
8t² + 2t + 3 = 0
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
F = ma
∫₀^∞ e^(-φ²) dφ = √π / 2