Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:41Z
2ψ² + 5ψ + 4 = 0
det| 9 4 ; 1 10 | = 86
75K
N₂ + 3H₂ ⇌ 2NH₃
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
det| 5 9 ; 7 6 | = -33
191K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
390K
∇²z = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
1K
∑_{k=1}^{n} k = n(n+1)/2
153K
N₂ + 3H₂ ⇌ 2NH₃
det| 4 6 ; 4 5 | = -4
338K
8t² + 2t + 3 = 0
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1