Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 23:58Z
d/dα [α^11] = 11α^10
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\frac{3}{5} \sum_{i=1}^{n} i^{2}
det| 11 9 ; 0 12 | = 132
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λ = h/p
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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10r² + 3r + 0 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\frac{2}{2} \sum_{i=1}^{n} i^{2}
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