Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:40Z
2ψ² + 5ψ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
75K
det| 5 3 ; 2 6 | = 24
479K
N₂ + 3H₂ ⇌ 2NH₃
det| 3 3 ; 4 4 | = 0
129K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
det| 4 4 ; 5 5 | = 0
390K
det| 5 9 ; 7 6 | = -33
1K
∫₀^∞ e^(-t²) dt = √π / 2
338K