Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:36Z
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
75K
∫₀^∞ e^(-t²) dt = √π / 2
479K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
det| 9 4 ; 1 10 | = 86
276K
F = ma
det| 10 7 ; 3 11 | = 89
390K
10n² + 4n + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
473K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
338K
∫₀^∞ e^(-γ²) dγ = √π / 2