Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 23:49Z
d/dα [α^11] = 11α^10
det| 4 6 ; 4 5 | = -4
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\frac{3}{5} \sum_{i=1}^{n} i^{2}
det| 10 9 ; 0 11 | = 110
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det| 11 9 ; 0 12 | = 132
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λ = h/p
10r² + 3r + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
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det| 5 3 ; 2 6 | = 24
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