Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:29Z
∇ × E = −∂B/∂t
\binom{n}{k} = \frac{n!}{k!(n-k)!}
479K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
det| 11 5 ; 0 12 | = 132
129K
F = ma
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
191K
∫₀^∞ e^(-x²) dx = √π / 2
1K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
473K
\oint_C \vec{F}\cdot d\vec{r} = 0
188K